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angle of Θ_T =56° with respect to the tension axis. Such shear fracture behavior has been widely observed in many metallic glasses, as summarized in the literatures[3,4] and Table 1.[5–14] According to the definition in the textbooks,[1,2] the tensile fracture strength of the metallic glass should be equal to rT=Fmax/A0. However, the actual area of the shear fracture surface becomes A0/sin(Θ_T) and the applied normal tensile force on the shear plane is Fmax cos(hT), as shown in Figure 1. This will result in another tensile strength F_maxsin(Θ_T)cos(Θ_T)/A0, which is different from that (F_max/A0) defined in textbooks.[1,2] Consequently, this gives rise to some interesting and significant questions. Which is the real tensile strength of a metallic glass, F_max/A0 or F_maxsin(Θ_T)cos(Θ_T)/A0? Why do metallic glasses often fail neither along the maximum normal stress plane (Θ_T =90°) nor along the maximum shear stress plane (Θ_TT =45 °) under tensile loading[5–14]? What is the physical nature of the materials strength?

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